b^2+12b-28=0

Solution for b^2+12b-28=0 equation:

Simplifying
b2 + 12b + -28 = 0

Reorder the terms:
-28 + 12b + b2 = 0

Solving
-28 + 12b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-14 + -1b)(2 + -1b) = 0

Subproblem 1
Set the factor '(-14 + -1b)' equal to zero and attempt to solve:

Simplifying
-14 + -1b = 0

Solving
-14 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '14' to each side of the equation.
-14 + 14 + -1b = 0 + 14

Combine like terms: -14 + 14 = 0
0 + -1b = 0 + 14
-1b = 0 + 14

Combine like terms: 0 + 14 = 14
-1b = 14

Divide each side by '-1'.
b = -14

Simplifying
b = -14
Subproblem 2
Set the factor '(2 + -1b)' equal to zero and attempt to solve:

Simplifying
2 + -1b = 0

Solving
2 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1b = 0 + -2
-1b = 0 + -2

Combine like terms: 0 + -2 = -2
-1b = -2

Divide each side by '-1'.
b = 2

Simplifying
b = 2
Solution
b = {-14, 2}